3.16 \(\int \frac {1-x}{1+x^3} \, dx\)

Optimal. Leaf size=22 \[ \frac {2}{3} \log (x+1)-\frac {1}{3} \log \left (x^2-x+1\right ) \]

[Out]

2/3*ln(1+x)-1/3*ln(x^2-x+1)

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Rubi [A]  time = 0.01, antiderivative size = 22, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 13, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.231, Rules used = {1860, 31, 628} \[ \frac {2}{3} \log (x+1)-\frac {1}{3} \log \left (x^2-x+1\right ) \]

Antiderivative was successfully verified.

[In]

Int[(1 - x)/(1 + x^3),x]

[Out]

(2*Log[1 + x])/3 - Log[1 - x + x^2]/3

Rule 31

Int[((a_) + (b_.)*(x_))^(-1), x_Symbol] :> Simp[Log[RemoveContent[a + b*x, x]]/b, x] /; FreeQ[{a, b}, x]

Rule 628

Int[((d_) + (e_.)*(x_))/((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Simp[(d*Log[RemoveContent[a + b*x +
c*x^2, x]])/b, x] /; FreeQ[{a, b, c, d, e}, x] && EqQ[2*c*d - b*e, 0]

Rule 1860

Int[((A_) + (B_.)*(x_))/((a_) + (b_.)*(x_)^3), x_Symbol] :> With[{r = Numerator[Rt[a/b, 3]], s = Denominator[R
t[a/b, 3]]}, -Dist[(r*(B*r - A*s))/(3*a*s), Int[1/(r + s*x), x], x] + Dist[r/(3*a*s), Int[(r*(B*r + 2*A*s) + s
*(B*r - A*s)*x)/(r^2 - r*s*x + s^2*x^2), x], x]] /; FreeQ[{a, b, A, B}, x] && NeQ[a*B^3 - b*A^3, 0] && PosQ[a/
b]

Rubi steps

\begin {align*} \int \frac {1-x}{1+x^3} \, dx &=\frac {1}{3} \int \frac {1-2 x}{1-x+x^2} \, dx+\frac {2}{3} \int \frac {1}{1+x} \, dx\\ &=\frac {2}{3} \log (1+x)-\frac {1}{3} \log \left (1-x+x^2\right )\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 22, normalized size = 1.00 \[ \frac {2}{3} \log (x+1)-\frac {1}{3} \log \left (x^2-x+1\right ) \]

Antiderivative was successfully verified.

[In]

Integrate[(1 - x)/(1 + x^3),x]

[Out]

(2*Log[1 + x])/3 - Log[1 - x + x^2]/3

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fricas [A]  time = 0.48, size = 18, normalized size = 0.82 \[ -\frac {1}{3} \, \log \left (x^{2} - x + 1\right ) + \frac {2}{3} \, \log \left (x + 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-x)/(x^3+1),x, algorithm="fricas")

[Out]

-1/3*log(x^2 - x + 1) + 2/3*log(x + 1)

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giac [A]  time = 0.17, size = 19, normalized size = 0.86 \[ -\frac {1}{3} \, \log \left (x^{2} - x + 1\right ) + \frac {2}{3} \, \log \left ({\left | x + 1 \right |}\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-x)/(x^3+1),x, algorithm="giac")

[Out]

-1/3*log(x^2 - x + 1) + 2/3*log(abs(x + 1))

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maple [A]  time = 0.04, size = 19, normalized size = 0.86 \[ \frac {2 \ln \left (x +1\right )}{3}-\frac {\ln \left (x^{2}-x +1\right )}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((1-x)/(x^3+1),x)

[Out]

2/3*ln(x+1)-1/3*ln(x^2-x+1)

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maxima [A]  time = 2.47, size = 18, normalized size = 0.82 \[ -\frac {1}{3} \, \log \left (x^{2} - x + 1\right ) + \frac {2}{3} \, \log \left (x + 1\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-x)/(x^3+1),x, algorithm="maxima")

[Out]

-1/3*log(x^2 - x + 1) + 2/3*log(x + 1)

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mupad [B]  time = 0.11, size = 18, normalized size = 0.82 \[ \frac {2\,\ln \left (x+1\right )}{3}-\frac {\ln \left (x^2-x+1\right )}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-(x - 1)/(x^3 + 1),x)

[Out]

(2*log(x + 1))/3 - log(x^2 - x + 1)/3

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sympy [A]  time = 0.23, size = 17, normalized size = 0.77 \[ \frac {2 \log {\left (x + 1 \right )}}{3} - \frac {\log {\left (x^{2} - x + 1 \right )}}{3} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((1-x)/(x**3+1),x)

[Out]

2*log(x + 1)/3 - log(x**2 - x + 1)/3

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